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Dec 19, 2004 · Subspace is a term frequently used in science fiction, particularly in shows like Star Trek and Stargate, to describe a hypothetical dimension that allows for faste~Jan 21, 2009 · No, because the subspace will have negatives of elements, i.e., for all v an element of V, (-1)v or -v will be an element. For the subspace to be closed under addit$Oct 5, 2014 · I am trying to determine how to tell if a set is a subspace. The problem reads like this: Determine if the described set is a subspace. If so, give a proof. If not, @Jan 24, 2024 · Can a vector subspace have the same dimension as the space it is part of? If so, can such a subspace have a Cartesian equation? if so, can you give an example. Than|Oct 13, 2025 · Hi, A quick question: Does a set need to be a subset to be a subspace of some vector space?%Jan 27, 2013 · Homework Statement Is U = {A| A \\in nân, A is invertible} a subspace of nân, the space of all nxn matrices? The Attempt at a Solution This is easy to prove if +Aug 25, 2006 · I think R2 is a subspace of R3 in the form (a,b,0).
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Dec 19, 2004 · Subspace is a term frequently used in science fiction, particularly in shows like Star Trek and Stargate, to describe a hypothetical dimension that allows for faste~Jan 21, 2009 · No, because the subspace will have negatives of elements, i.e., for all v an element of V, (-1)v or -v will be an element. For the subspace to be closed under addit$Oct 5, 2014 · I am trying to determine how to tell if a set is a subspace. The problem reads like this: Determine if the described set is a subspace. If so, give a proof. If not, @Jan 24, 2024 · Can a vector subspace have the same dimension as the space it is part of? If so, can such a subspace have a Cartesian equation? if so, can you give an example. Than|Oct 13, 2025 · Hi, A quick question: Does a set need to be a subset to be a subspace of some vector space?%Jan 27, 2013 · Homework Statement Is U = {A| A \\in nân, A is invertible} a subspace of nân, the space of all nxn matrices? The Attempt at a Solution This is easy to prove if +Aug 25, 2006 · I think R2 is a subspace of R3 in the form (a,b,0).